2(2x^2+1)=5x

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Solution for 2(2x^2+1)=5x equation: 



2(2x^2+1)=5x

We move all terms to the left:

2(2x^2+1)-(5x)=0

We add all the numbers together, and all the variables

-5x+2(2x^2+1)=0

We multiply parentheses

4x^2-5x+2=0

a = 4; b = -5; c = +2;
Δ = b2-4ac
Δ = -52-4·4·2
Δ = -7
Delta is less than zero, so there is no solution for the equation

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